[CentOS] Find user accounts with uid > 500
William L. Maltby
CentOS4Bill at triad.rr.comThu Feb 28 09:27:03 UTC 2008
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On Thu, 2008-02-28 at 02:56 -0600, Sean Carolan wrote: > Hi all: > > I'm doing an audit of some Linux machines, and have used this awk > one-liner to find accounts with uid > 499: > > awk -F: '{if ($3 > 499) print $0}' < /etc/passwd > > It works great if you run it on a host directly, but if I try to ssh > to a remote host and run the command it fails: > > mybox$ ssh servername awk -F: '{if ($3 > 499) print $0}' < /etc/passwd > > bash: -c: line 1: syntax error near unexpected token `(' > bash: -c: line 1: `awk -F: {if ($3 > 499) print $0}' > > I tried wrapping the command in quotes but no luck. Any suggestions? > I want to put this into a for loop so I can grab the info from > multiple machines. ssh servername awk -F: "'{if (\$3 > 499) print \$0}'" < /etc/passwd > > thanks > > Sean > <snip sig stuff> -- Bill
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