[CentOS] Format details for a raid partition....

John Doe jdmls at yahoo.com
Mon Oct 4 08:22:13 EDT 2010


From: Tom Bishop <bishoptf at gmail.com>
>So I have been playing with a RAID 10 f2 ( 2 disks far layout) setup...thanks 
>for all of the advice..Now I am playing with the format and want to make sure I 

>have it setup the best that I can, my raid was built using the raid 10 option 
>with 2 disks with the layout=far, chunk size 512....now I read all of the docs I 
>
>could find about format and stride and stripe size and this is what i came up 
>with...
>mkfs -t ext4 -E stride=128,stripe-width=32 /dev/md0
>Someone let meknow if this looks right, but since i only have two disks to get 
>my stride 512/4k=128 and then to get my stripe 2/2*128/4=32

>From the mke4fs man page:
"stripe-width ... This  is  typically  stride-size * N, where N is 
the number of data-bearing disks in the  RAID"

So, I think it is 128 * 1 = 128

Also, have a look at:
http://busybox.net/~aldot/mkfs_stride.html

JD


      


More information about the CentOS mailing list