I want a script to determine the owner of a particular file and then "sudo -u <thatuserid> <somecomand>". I ran across the --author option of ls but that does not seem to give me anything useful. It prints a short form of the filename without any other information at all. In fact, the output of ls --author is indistinguishable from that of ls by itself:
# ls --author htdocs/* htdocs/hlllogo.png # ls htdocs/* htdocs/hlllogo.png #
Is there a linux command that will return just the userid in a form that can be passed to sudo or do I have to parse ls -l <filename>?
I am digest subscriber so, if you could provide one, the favour of a direct copy of your reply is requested.
Regards, Jim
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