3 Aug
2012
3 Aug
'12
1:54 p.m.
[For the archives, since I think Johnny just hit the wrong number key.....]
On Thursday, August 02, 2012 10:24:27 AM Johnny Hughes wrote:
If you want 8 usable addresses (including the Network number, a gateway address, and a Broadcast address), that would mean you need at least 11 IPs in that subnet ... the closest fit would be a 255.255.255.240 subnet (which has 16 addresses). If you were to want to use th 255.255.255.240 subnet, then 192.168.1.48 would not be available as it would the the Network number for that subnet ... the usable addresses would be 192.168.1.49-63 that case and the Broadcast Address would be 192.168.1.64
192.168.1.63 would be the correct broadcast address; .64 would be the network address of the next subnet.