On 04/22/2016 09:43 AM, g wrote:
]$ sudo blockdev --getalignoff /dev/sdc1 0 ]$ sudo blockdev --getalignoff /dev/sdc2 0 ]$ sudo blockdev --getalignoff /dev/sdc5 2560 ]$ sudo blockdev --report /dev/sdc1 RO RA SSZ BSZ StartSec Size Device rw 256 512 4096 2048 838860800 /dev/sdc1 ]$ sudo blockdev --report /dev/sdc2 RO RA SSZ BSZ StartSec Size Device rw 256 512 4096 1640448 1048576000 /dev/sdc2 ]$ sudo blockdev --report /dev/sdc5 RO RA SSZ BSZ StartSec Size Device rw 256 512 4096 33848955 328282081792 /dev/sdc5
so, blockdev does not show end, but does confirm sdc5 start is off by 2560, same as fdisk.
all of which indicates i should repartition drive with fdisk.
is there any easier way such as using gparted or sparted so that partitioning will be by cylinder and not sector?
You do not want to partition by cylinder. The CHS geometry that fdisk reports has been meaningless on hard disks for at least the last 10 years and bears no relationship to the actual cylinders on the drive. At that arbitrary 255 heads 63 sectors/track geometry, you might have to skip over 7 full "cylinders" to find one that starts on a 4096-byte boundary. The version of fdisk in CentOS 6 is old, and still defaults to the deprecated cylinder units. You should always switch to sector units when using it. The warning about partitions that do not start or end on a cylinder boundary should be ignored.