5 Jan
2009
5 Jan
'09
8:16 p.m.
On Mon, 5 Jan 2009, Joseph L. Casale wrote:
The regex you want is "^[[:space:]]*word"
Wow, thanks everyone for the help! How does one modify this to also knock out lines that *must* have whitespace followed by a number [0-9]? I can do it using "^[[:space:]]*[0-9]" but it also takes out lines w/o whitespace that begin with numbers?
Probably something like "^[[:space:]]+[0-9]"
-- though that assumes you're using gawk (since the + modifier is GNU-specific).
For non-GNU awks, "^[[:space:]][[:space:]]*[0-9]"
I have to buy a book on RegEx's and Sed :)
Good idea!
--
Paul Heinlein <> heinlein@madboa.com <> http://www.madboa.com/