9 Mar
2006
9 Mar
'06
12:22 p.m.
On Thursday 09 March 2006 07:12 pm, Nick wrote:
Running with 1 disk down the array will function at 100% as all the data is still available because of the parity info stored on the two good disks. The problem is with one disk down you have absolutely no redundancy. If one of the other disks failed the data would be lost for ever. If you replace the dead disk you can then start rebuilding the array so that you get your redundancy back.
this page explains it a lot better than i can http://www1.us.dell.com/content/topics/global.aspx/power/en/ps2q03_luse?c=u s&l=en&s=corp
Thank you very much Nick. It really gives me a clear understanding.
--
Fajar Priyanto | Reg'd Linux User #327841 | Linux tutorial
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