On Thu, Dec 3, 2009 at 12:42 PM, mark m.roth@5-cent.us wrote:
John Doe wrote:
From: hadi motamedi motamedi24@gmail.com
Can you please do me favor and let me know if I can go further and try
for
advanced search like finding how many rows inside a file have data that does not start with a zero after the third comma ?
Something like: awk -F, ' { print $4 } ' | grep -v "^0" | wc -l Use one command at a time to see how they work with each other (you might have to modify the grep a bit)...
*sigh*
Drive me crazy, why use multiple commands?
awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print count }' filename
mark "why, yes, since you ask, I *have* written 100 and 200 line awk scripts"-- Though I don't think (object-oriented programming) has much to offer good programmers, except in certain specialized domains, it is irresistible to large organizations. Object-oriented programming offers a sustainable way to write spaghetti code. - Paul Graham _______________________________________________ CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos
Sorry . I tried for your proposed procedure , as the followings : #awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print count }' HLRSubscriber-20091111173349.csv But my CentOS server didn't return to the prompt . Can you please let me know why it is in an end-less iterated loop ? Thank you in advance