On Thursday 24 September 2009, Nathan Norton wrote: ...
All 10 drives are 2T in size.
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# mdadm --create --verbose /dev/md3 --level=6 --raid-devices=10 /dev/sda1 /dev/sdb1 /dev/sdc1 /dev/sdd1 /dev/sde1 /dev/sdf1 /dev/sdi1 /dev/sdj1 /dev/sdk1 /dev/sdl1 mdadm: layout defaults to left-symmetric mdadm: chunk size defaults to 64K mdadm: size set to 1953511936K Continue creating array?
As you can see mdadm sets the size to 1.9T
1953511936K (KiB, 2*2^40) is equal to 2 TB (2*10^12) no mystery here.
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# mdadm --detail /dev/md3 /dev/md3: Version : 0.90 Creation Time : Thu Sep 24 23:48:32 2009 Raid Level : raid6 Array Size : 15628095488 (14904.11 GiB 16003.17 GB) Used Dev Size : 1953511936 (1863.01 GiB 2000.40 GB)
16003.17 GB (10^9) is exactly what you should get (10 drives -2 for parity times 2 TB).
/Peter
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Anyone got any ideas?
Nathan