16 May
2019
16 May
'19
6:57 p.m.
I have a simple bash script it will take arguments from a file that has quotes.
my file arg.txt would be this -lt "*.txt"
my script file would be LS_ARG=`cat arg.txt` ls $LS_ARG
it does not run properly: sh -x ./arg.sh ++ cat arg.txt + LS_ARG='-lt "*.txt"' + ls -lt '"*.txt"' ls: cannot access "*.txt": No such file or directory
How do I resolve that ? If the quotes are not in my file it all works fine. I think its because it looks like the extra single quotes it puts around the "*.txt" - or - '"*.txt"' - how do I do this ? This is just a short example of my larger need.
Thanks,
Jerry