On Tue, September 4, 2012 16:51, Les Mikesell wrote:
That should happen directly without C's involvement if the netmask is 255.255.0.0 on A and B's eth1 interfaces.
It is not. The netmask on those interfaces is 255.255.255.0.
Instead it goes to Eth0 on C where it dies as one would expect.
Why does C have both internet and LAN addresses on the same interfaces?
I am experimenting to see if this arrangement is workable. I want to know if it is possible to have two separate 192.168.x subnets on the same network. Why? I do not have a purpose in mind. I am just checking out whether it can work or not.
If it is impossible then then I will discover why that is so, which I think will be useful in itself.