On Sat, Mar 5, 2011 at 5:13 PM, Patrick Lists centos-list@puzzled.xs4all.nl wrote:
Hi,
My grep regex foo is not very good and googling is getting me nowhere so hopefully someone is kind enough to give me some pointers.
Goal: grep (non .dbg) filenames and versions from a ftp dir listing and a raw html file:
$ wget --no-remove-listing -O ftp-index.txt ftp://127.0.0.1/test/ $ wget --no-remove-listing -O index.html http://127.0.0.1/test/
The relevant parts of the files above (first one is ftp listing, second part is the html file, both copied to test_regex.txt) are:
2011 Jan 28 21:25 File <a href="ftp://127.0.0.1/bar-4.5.6.i686.dbg.tgz">bar-4.5.6.i686.dbg.tgz</a> (5551274 bytes) 2011 Jan 28 21:25 File <a href="ftp://127.0.0.1/bar-4.5.6.i686.tgz">bar-4.5.6.i686.tgz</a> (5551274 bytes) 2011 Jan 28 21:25 File <a href="ftp://127.0.0.1/bar-4.5.6.x86_64.dbg.tgz">bar-4.5.6.x86_64.dbg.tgz</a> (5551274 bytes) 2011 Jan 28 21:25 File <a href="ftp://127.0.0.1/bar-4.5.6.x86_64.tgz">bar-4.5.6.x86_64.tgz</a> (5551274 bytes)
<tr><td><a href="foo-bar-1.2.3+1.2.3.tar.gz">foo-bar-1.2.3+1.2.3.tar.gz</td></tr>
This is what I now have (improvements most welcome):
$ egrep -o ">([A-Za-z_-]+)([[:digit:]]{1,3}(.[[:digit:]]{1,3})*).+(.|t)gz" ./test_regex.txt | grep -v ".dbg" | tr -d '>'
Output:
foo-bar-1.2.3+1.2.3.tar.gz baz-4.5.6.i686.tgz baz-4.5.6.x86_64.tgz
So far so good but now I also want to get the version numbers which I can't figure out. Anyone have a pointer how to get the version number from these filenames (1.2.3+1.2.3 and 4.5.6)?
Separate the ".i686.tgz" with something like a '-' or "_", not a dot. and be consistent about using .tar.gz instead of mixing .tar.gz and .tgz, if possible.