From: S Mathias smathias1972@yahoo.com
$ ASDF=hello; a=0; a=$(( 70 - $(echo $ASDF | awk '{print length}') )); echo "$a $ASDF"$(for i in {1..$a}; do printf "."; done) 65 hello. Why doesn't it print: 65 hello................................................................. What am i missing?
$ for i in {1..3}; do echo $i; done 1 2 3 $ a=3; for i in {1..$a}; do echo $i; done {1..3}
Try with: for ((i=1;i<=$a;i++))
JD