[CentOS] OT ? Shell script
Jonathan Wright
mailing-lists at djnauk.co.uk
Sun Dec 4 21:18:12 UTC 2005
� wrote:
> How about something like:
>
> YEAR=2005
> MONTH=12
> for ((DAY=1;DAY<=31;++DAY)); do
> LC_ALL=C TZ=UTC date -d "$YEAR-$MONTH-$DAY"
> done | grep "^Mon " | head -n 3 | tail -n 1
>
> Possibly without the TZ=UTC depending on your needs...
A better and faster option is to work out what day of the week the 21st
falls on (e.g. Wednesday, or 4) and count back that value (minus 1 to
count for Sunday):
M=12
Y=2005
echo date +%d -d $Y/$M/$((21-$(($(date +%w -d $Y/$M/21)-1))))
--
Jonathan Wright
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