James B. Byrne wrote: > I want a script to determine the owner of a particular file and > then "sudo -u <thatuserid> <somecomand>". I ran across the --author > option of ls but that does not seem to give me anything useful. It > prints a short form of the filename without any other information > at all. In fact, the output of ls --author is indistinguishable > from that of ls by itself: > > >> # ls --author htdocs/* >> htdocs/hlllogo.png >> # ls htdocs/* >> htdocs/hlllogo.png >> # > > > Is there a linux command that will return just the userid in a form > that can be passed to sudo or do I have to parse ls -l <filename>? > > > I am digest subscriber so, if you could provide one, the favour of > a direct copy of your reply is requested. > > Regards, > Jim > > -- > *** e-mail is not a secure channel *** > mailto:byrnejb.<token>@harte-lyne.ca > James B. Byrne Harte & Lyne Limited > vox: +1 905 561 1241 9 Brockley Drive > fax: +1 905 561 0757 Hamilton, Ontario > <token> = hal Canada L8E 3C3 > > _______________________________________________ > CentOS mailing list > CentOS at centos.org > http://lists.centos.org/mailman/listinfo/centos > > ls -l <filename> | awk '{print $3}' will give you the owner of the file.