On Fri, 2008-03-07 at 11:59 -0500, Ross S. W. Walker wrote: > Ross S. W. Walker wrote: > > Jerry Geis wrote: > > > > > > Hi - I am not an expert at shell script writing. > > > If /proc/cmdline looks like > > > > > > option1 option2 ... ks=http://192.168.1.8/ks/ks.cfg option3 > > > option 4 ... > > > > > > How can I get the 192.168.1.8 out of this cmdline. > > > > Try: > > > > # IPADDR=`cat /proc/cmdline | sed 's/.*\/\([1-9][0-9]*\.[0-9][0-9]*\.[0-9][0-9]*\.[0-9][0-9]*\)\/.*/\1/'` > > > > This will find an IP in between /.../ > > Actually shorter sed line: > > # IPADDR=`cat /proc/cmdline | sed 's/.*\/\([0-9]\+\.[0-9]\+\.[0-9]\+\.[0-9]\+\)\/.*/\1/'` And shorter still: sed 's/.*\/\(\([0-9]\+\.\)\{3,\}[0-9]\+\).*/\1/' which uses \{3,\} to specify the 3 occurrences of [0-9]\+\. However, I would simply go for something like: sed 's,.*http://\(.*\)/ks/.*,\1,' Jim