From: mark <m.roth at 5-cent.us> > John Doe wrote: > > From: hadi motamedi > >> Can you please do me favor and let me know if I can go further and try for > >> advanced search like finding how many rows inside a file have data that > >> does not start with a zero after the third comma ? > > > > Something like: awk -F, ' { print $4 } ' | grep -v "^0" | wc -l Use one > > command at a time to see how they work with each other (you might have to > > modify the grep a bit)... > > *sigh* > > Drive me crazy, why use multiple commands? > > awk -F 'BEGIN { FS = ","; }{if ( $3 !~ /^0 ) { count++; }} END { print count }' > filename Oh no!!! Don't get mad!!! ^_^ Teaching some UNIX pipes to a "beginner" can be helpful you know... And it is $4... JD