From: James Bensley <jwbensley at gmail.com> > > But probably someone will come up with a small c program which eats all > > available memory :) > I would be interested in such a program if anyone has one or a mega > bash script that can achive the same? Quick, dirty and unoptimized (and barely tested, might not work past 4GB)... ^_^ - - - - - -8<- - - - - - - - - - - -8<- - - - - - - - - - - -8<- - - - - - #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { FILE *fs; int i; long j; int mem_total; int mem_free; int mem_buffered; int mem_cached; int mem_to_fill; char *megabuff[1024]; fs = fopen("/proc/meminfo", "r"); fscanf(fs, "%*s %d %*s\n", &mem_total); fscanf(fs, "%*s %d %*s\n", &mem_free); fscanf(fs, "%*s %d %*s\n", &mem_buffered); fscanf(fs, "%*s %d %*s\n", &mem_cached); fclose(fs); mem_to_fill = (mem_free+mem_buffered+mem_cached+1024)*sizeof(char); printf("Filling %dKB...\n", mem_to_fill); for (i=0; i<1024; i++) { if ((megabuff[i] = malloc(mem_to_fill)) == NULL) { fprintf(stderr, "malloc error..."); } else { for (j=0; j<mem_to_fill; j++) { megabuff[i][j] = '1'; } } } for (i=0; i<1024; i++) { free(megabuff[i]); } } - - - - - -8<- - - - - - - - - - - -8<- - - - - - - - - - - -8<- - - - - - Then swapoff /dev/..; swapon /dev/... to clean... JD