You could pass the value of $LINENO to Line() as a function argument:
Here's the one file (func-file):
-------------------------
Line()
{
echo This is line $@
}
-------------------------
That one is called by this one:
-------------------------
#!/bin/bash
. ./func-file
Line $LINENO
------------------------
Macintosh-5:/tmp joshuagimer$ cat func-file
Line()
{
echo This is line $@
}
Macintosh-5:/tmp joshuagimer$ cat test.sh
#!/bin/bash
. ./func-file
Line $LINENO
Macintosh-5:/tmp joshuagimer$ bash test.sh
This is line 5
Thanks
Josh
On Sat, Nov 14, 2009 at 5:37 PM, ken <gebser at mousecar.com> wrote:
> It's half a nice Saturday later and many attempts have brought no
> satisfaction. Maybe this can't be done.
>
> I'm trying to write a function which, when called from one function
> execute in another. In itself, that's not the problem. Rather, there's
> one built-in variable which is evaluated in the function definition and
> it's value is then set (too early).
>
> Here's the one file (func-file):
> -------------------------
> Line()
> {
> echo This is line "$LINENO" $@
> }
> -------------------------
>
> That one is called by this one:
> -------------------------
> #!/bin/bash
>
> . ./func-file
>
> Line ... it should be $LINENO
> ------------------------
>
> I want the function Line to show the line number in the second file
> where it's executed, not the line number from the sourced function.
>
> Any mavens got the skinny on this?
>
> tia
>
>
> --
> War is a failure of the imagination.
> --William Blake
>
> _______________________________________________
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> CentOS at centos.org
> http://lists.centos.org/mailman/listinfo/centos
>
--
Thx
Joshua Gimer
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