[CentOS] Stripe vs Cylinder alignement...

Fri Oct 30 15:04:28 UTC 2009
John Doe <jdmls at yahoo.com>

> So, for my first partition (96MB):
>   begin=256
>   size = ( ( 96 * 1024 * 2 ) / 8160 ) * 8160 = 195840 sectors
>   end = 195840 - 1 - 256 = 195583

Oops, I meant:

  begin = 256
  size = 96 * 1024 * 2 = 196608 sectors
  end = ( ( begin + size ) / 8160 ) * 8160 - 1 = 195839
  aligned_size = end - begin + 1 = 195584

Maybe... I am a bit confused  ^_^

JD