> Need a scripting help to sort out a list and list all the duplicate lines.
>
> My data looks somethings like this
>
> host6:dev406mum.dd.mum.test.com:22:11:11:no
> host7:dev258mum.dd.mum.test.com:36:17:19:no
> host7:dev258mum.dd.mum.test.com:36:17:19:no
> host17:dev258mum.dd.mum.test.com:31:17:19:no
> host12:dev258mum.dd.mum.test.com:41:17:19:no
> host2:dev258mum.dd.mum.test.com:36:17:19:no
> host4:dev258mum.dd.mum.test.com:41:17:19:no
> host4:dev258mum.dd.mum.test.com:45:17:19:no
> host4:dev258mum.dd.mum.test.com:36:17:19:no
>
> I need to sort this list and print all the lines where column 3 has a
> duplicate entry.
>
> I need to print the whole line, if a duplicate entry exists in column 3.
>
> I tried using a combination of "sort" and "uniq" but was not successful.
list.awk
BEGIN {
FS=":";
}
{ if ( $3 == last ) {
print $0;
}
last = $3;
}
sort <file> | awk -f list.awk
mark "*how* long an awk script would you like?"