[For the archives, since I think Johnny just hit the wrong number key.....] On Thursday, August 02, 2012 10:24:27 AM Johnny Hughes wrote: > If you want 8 usable addresses (including the Network number, a gateway > address, and a Broadcast address), that would mean you need at least 11 > IPs in that subnet ... the closest fit would be a 255.255.255.240 subnet > (which has 16 addresses). If you were to want to use th 255.255.255.240 > subnet, then 192.168.1.48 would not be available as it would the the > Network number for that subnet ... the usable addresses would be > 192.168.1.49-63 that case and the Broadcast Address would be 192.168.1.64 192.168.1.63 would be the correct broadcast address; .64 would be the network address of the next subnet.