Hi, I'm wanting to configure a CentOS 6 server to have a fall-back default route via a second network interface. Given: - eth0 with 192.168.0.10 on subnet 192.168.0.0/24 gateway 192.168.0.1 - eth1 with 192.168.1.10 on subnet 192.168.1.0/24 gateway 192.168.1.1 Where eth0's network is a "back door" to the internet, and eth1's is the "front door", I believe I can configure the routing table manually like this: ip route default scope global \ nexthop via 192.168.1.1 dev eth1 weight 1 \ nexthop via 192.168.0.1 dev eth0 weight 2 However, I've re-read the RHEL6 documents for configuring static routes here: http://docs.redhat.com/docs/en-US/Red_Hat_Enterprise_Linux/6/html/Deployment_Guide/s1-networkscripts-static-routes.html This kind of thing doesn't seem to fit into the scheme of /etc/sysconfig/network-scripts/route-eth? described there, since the route isn't "for" any single interface. Is there a "RHEL/CentOS" way to do this, or do I need to resort to some sort of script containing the above ip route command inserted somewhere? And how do I stop CentOS from trying to pick its own default gateway settings (since /etc/sysconfig/network likely won't have a GATEWAY parameter)? Cheers, Nick ps. Hints about this obtained from http://lkml.indiana.edu/hypermail/linux/net/0201.0/0000.html http://lartc.org/lartc.html#AEN298