On 6/3/2014 11:55 AM, Tim Dunphy wrote: > Ok this is what I came up with: > > #!/bin/bash > # this script parses mod_status to see which hosts are getting the most > requests > > while true > do > echo "Time and date: $(/bin/date +"%D %H:%M:%S")" >> > /tmp/apache_request_log >> /tmp/apache_request_log > echo “hostname: $(/bin/hostname -f)\n” >> /tmp/apache_request_log > echo “host ip: $(/bin/hostname -i)” >> /tmp/apache_request_log > echo "Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto | > /bin/egrep -i 'kbytes')" >> /tmp/apache_request_log > echo "Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto | > /bin/egrep -i 'ReqPerSec')" >> /tmp/apache_request_log > echo -e "\n" > sleep 60 > done > > Still can't get the echo -e "\n" statement to print a new line for some > reason. Other than that I'm good. And thanks for everyone's help! 'echo' on it's own should print a new line. If you want two, why not just use two echo lines? Also, you are piping everything else to the apache_request_log except for the last echo line. Is the problem simply that you forgot to pipe that to the log file? echo -e "\n" >> /tmp/apache_request_log -- Bowie