I want a script to determine the owner of a particular file and
then "sudo -u <thatuserid> <somecomand>". I ran across the --author
option of ls but that does not seem to give me anything useful. It
prints a short form of the filename without any other information
at all. In fact, the output of ls --author is indistinguishable
from that of ls by itself:
> # ls --author htdocs/*
> htdocs/hlllogo.png
> # ls htdocs/*
> htdocs/hlllogo.png
> #
Is there a linux command that will return just the userid in a form
that can be passed to sudo or do I have to parse ls -l <filename>?
I am digest subscriber so, if you could provide one, the favour of
a direct copy of your reply is requested.
Regards,
Jim
--
*** e-mail is not a secure channel ***
mailto:byrnejb.<token>@harte-lyne.ca
James B. Byrne Harte & Lyne Limited
vox: +1 905 561 1241 9 Brockley Drive
fax: +1 905 561 0757 Hamilton, Ontario
<token> = hal Canada L8E 3C3