I would like to run a program at 2:35 at the first Saturday of each odd month.
My solution: 35 2 1-7 1,3,5,7,9,11 6 /bin/program
The program was executed yesterday = Wednesday = day 3, cron ignores the day of the week!
Is there a solution with cron - or have I to write a script to check the date?
Helmut
Helmut Drodofsky wrote:
I would like to run a program at 2:35 at the first Saturday of each odd month.
My solution:
35 2 1-7 1,3,5,7,9,11 6 /bin/program
The program was executed yesterday = Wednesday = day 3, cron ignores the day of the week!
not ignoring, OR-ing: $ man 5 crontab <snip> Note: The day of a command’s execution can be specified by two fields — day of month, and day of week. If both fields are restricted (ie, aren’t *), the command will be run when either field matches the current time. For example, "30 4 1,15 * 5" would cause a command to be run at 4:30 am on the 1st and 15th of each month, plus every Friday. <snip>
don't know if there's a cleaner solution than using only eg saturday in cron and having a wrapper script for your program to check that it's the first week of a month.
On Thu, Jul 7, 2011 at 7:48 AM, Helmut Drodofsky drodofsky@internet-xs.de wrote:
I would like to run a program at 2:35 at the first Saturday of each odd month.
My solution:
35 2 1-7 1,3,5,7,9,11 6 /bin/program
The program was executed yesterday = Wednesday = day 3, cron ignores the day of the week!
Is there a solution with cron – or have I to write a script to check the date?
Helmut
The most elegant way I have seen to do this is:
35 2 1-7 1,3,5,7,9,11 * [ "$(date '+%a')" == "Sat" ] && command
This will run on the 1st through 7th days of the month, and if the day (as returned by "date +%a") is Sat, then execute the command. Otherwise do nothing.
I might also replace the month numbers with names, just to make it easier to understand (though the lines will get long):
35 2 1-7 Jan,Mar,May,Jul,Sep,Nov * [ "$(date '+%a')" == "Sat" ] && command
-☙ Brian Mathis ❧-
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Brian Mathis -
Helmut Drodofsky -
Nicolas Thierry-Mieg