On Dec 1, 2010, at 5:07 PM, Christopher Chan christopher.chan@bradbury.edu.hk wrote:

On Thursday, December 02, 2010 05:09 AM, ann kok wrote:

...

Hi all

Anyone can help to let me know how to

ls -1 | lsattr

lsattr `ls -1`

...

ls -al /folder | awk '{ print $2}' | lsattr

for i in `ls -al /folder | awk '{ print $8}'`; do lsattr /folder/$i; done

You can probably do that last one as a pipe to xargs instead of a shell loop.

-Ross

On Thursday, December 02, 2010 07:57 AM, Les Mikesell wrote:

On 12/1/2010 5:44 PM, Ross Walker wrote:

...

On Dec 1, 2010, at 5:07 PM, Christopher Chanchristopher.chan@bradbury.edu.hk wrote:

...

On Thursday, December 02, 2010 05:09 AM, ann kok wrote:

...

Hi all

Anyone can help to let me know how to

ls -1 | lsattr

lsattr `ls -1`

...

ls -al /folder | awk '{ print $2}' | lsattr

for i in `ls -al /folder | awk '{ print $8}'`; do lsattr /folder/$i; done

You can probably do that last one as a pipe to xargs instead of a shell loop.

I'm missing something here. Why does lsattr need help from ls?

It does not. I don't know why the OP is even trying to do it this way. Just thought I'd demonstrate some bash stuff. :-p