Hello Jerry-

Simply change the line:

newline=`echo $LINE | cut -f 19-`

to this:

newline=`echo $LINE | cut -c 19-`

You want to cut based on 'c'haracters, not 'f'ields. :-)

Tim Nelson Systems/Network Support Rockbochs Inc. (218)727-4332 x105

----- "Jerry Geis" geisj@pagestation.com wrote:

Hi all,

I am trying to create a script that takes an entire file, drops the first 19 characters from each line and creates a new file.

I am missing something easy but I am not seeing it.

Jerry

---

I tried the script below but did not work.

rm output.txt cat test.txt | \ while read LINE do newline=`echo $LINE | cut -f 19-` echo $newline >> output.txt done

test.txt is below 10-Oct-08 08:14 am 10 10-Oct-08 08:20 am 20 10-Oct-08 08:24 am 30 10-Oct-08 08:29 am 40 10-Oct-08 08:34 am 50 10-Oct-08 08:39 am 60 10-Oct-08 08:44 am 80 10-Oct-08 08:49 am 10 10-Oct-08 08:54 am 10 10-Oct-08 08:56 am 10

---

CentOS mailing list CentOS@centos.org http://lists.centos.org/mailman/listinfo/centos

Hi,

On Wed, Oct 15, 2008 at 10:48, Jerry Geis geisj@pagestation.com wrote:

I am trying to create a script that takes an entire file, drops the first 19 characters from each line and creates a new file. newline=`echo $LINE | cut -f 19-`

What you want is "cut -c 19-" (-c as in characters) and not "cut -f 19-" (-f as in fields).

  echo $newline >> output.txt

This will also remove the spacing. You should at least use echo "$newline" >>output.txt, but in any case it's silly as you can just:

cut -c 19- <test.txt >output.txt

HTH, Filipe

Jerry Geis wrote:

Hi all,

I am trying to create a script that takes an entire file, drops the first 19 characters from each line and creates a new file.

[..]

test.txt is below 10-Oct-08 08:14 am 10

If this is the format of your data you could use awk to do the same thing

cat filename | awk '{print $4}'

nate