[CentOS] Migrating software raid from SUSE 9.0 to Centos 5

Les Mikesell lesmikesell at gmail.com
Mon Jan 7 18:39:01 UTC 2008


Dan Carl wrote:
> 
> 
> 
> Dan Carl wrote:
>> I forgot to add the file system is riserfs.
>>
>> -----Original Message-----
>> From: centos-bounces at centos.org [mailto:centos-bounces at centos.org]On
>> Behalf Of Dan Carl
>> Sent: Friday, January 04, 2008 5:43 PM
>> To: centos at centos.org
>> Subject: [CentOS] Migrating software raid from SUSE 9.0 to Centos 5
>>
>>
>> I have a SUSE 9.0 box with a software raid.
>> It consists of 6 IDE drives and three different controllers
>> The OS is on a separate drive.
>> What I want to do is put a new boot drive in load Centos on it.
>> Then I want to be able to mount the raid without loosing any of the data
> on
>> it.
>> What information do I need from the SUSE OS (raid info etc...) to tell
>> Centos how to recognize it?
>> The data is backup on DVD's but it would be a real pain to reload it.(its
>> around a terabyte of data)
>> So I'm writing here for some advice.
>> I've setup many raids in the past but only fresh installs.
>> Thanks
> 
> After you do your base Centos install and 'yum update', do:
> yum --enablerepo=centosplus update kernel
> yum --enablerepo=centosplus install reiserfs-utils
> 
> Then reboot, and you should be able to mount the raid and add it to
> /etc/fstab.
> 
> Ok but how does Centos recognise the ARRAY?
> Is the Array's configuration stored some where?
> SUSE uses raidtab.
> The only raid type conf file on my other Centos boxes is /etc/mdadm.conf

If the partition type is FD, the kernel will autodetect and assemble it 
at boot time.

> So you mean to tell me I just have to make sure reiserfs is installed, then
> just mount like this in fstab
> /dev/md0             /home/tera           reiserfs   defaults              1
> 2
> #mount -a
> and bang everything in done?
> Something tells me it can't be that easy.

Before putting it in /etc/fstab, do a 'cat /proc/mdstat' to be sure that 
   md0 really exists and includes the right underlying devices, but yes, 
it should be that simple.

-- 
   Les Mikesell
    lesmikesell at gmail.com




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